A thin conducting ring of radius R is given a charge +Q. electric field at centre O of ring due

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1. Electric Charges and Fields

easy

A thin conducting ring of radius $R$ is given a charge $+Q.$ The electric field at the centre $O$ of the ring due to the charge on the part $AKB$ of the ring is $E.$ The electric field at the centre due to the charge on the part $ACDB$ of the ring is

A

$E$ along $KO$

B

$3E$ along $OK $

C

$3E$ along $KO$

D

$E$ along $OK$

(AIPMT-2008)

Solution

The fields at $O$ due to $AC$ and $BD$ cancel each other.

The field due to $CD$ is acting in the direction $OK$ and equal in magnitude to $E$ due to $AKB$.

Standard 12

Physics

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